Reputation: 335
I have a list of strings (List[String]
) and I want to obtain the most frequent string from this list:
val list1 = List('a','a','0','b','b','a')
The answer should be:
freq_list1 = a
I was thinking to use list1.sliding(2).count...
in order to get the count of unique string, but I don't know how to wrap it into finding the most frequent string.
Upvotes: 1
Views: 1004
Reputation: 37832
list1.groupBy(identity).mapValues(_.size).maxBy(_._2)._1
EDIT: See comment below, can be made shorter by using maxBy(_._2.size)
without mapping beforehand, thanks @kawty
Upvotes: 4