lukas kiss
lukas kiss

Reputation: 392

sympy solve linear equations XOR, NOT

I have 60 equations with 70 variables. all of them are in one list:

(x0,x1,...,x239) are sympy symbols

list_a = [Xor(Not(x40), Not(x86)), Xor(x41, Not(x87)), ...]

and my question is, if it is possible somehow transform this equations to matrix or solved them. I think, that it can have more than one solution.

Upvotes: 2

Views: 1387

Answers (1)

asmeurer
asmeurer

Reputation: 91610

A solution to a system of logic expressions is the same as checking SAT for the conjunction (And) of the expressions.

In [3]: list_a = [Xor(Not(x40), Not(x86)), Xor(x41, Not(x87))]

In [4]: list_a
Out[4]: [¬x₄₀ ⊻ ¬x₈₆, x₄₁ ⊻ ¬x₈₇]

In [5]: satisfiable(And(*list_a))
Out[5]: {x87: False, x40: True, x86: False, x41: False}

If you want all solutions you can pass all_models=True, although note that in the general case there are exponentially many solutions.

Upvotes: 2

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