CODEWITHSUNDEEP
arraysrubyif-statementinclude
and1ball0032
and1ball0032

Reputation: 39

Selecting a single element from an array, within an "if" statement

Creating a method that receives input from a user -- and if said input includes any word from a predetermined array, it prints the word "success!" Otherwise, if the input doesn't include a word from that array, it prints the word "failure."

My ideal would be to create a scenario where I can populate the array with as many elements as I want, and the method will always reference that array when deciding how to react to the user's input.

When I run it, however, I get an error message saying "no implicit conversion of Array into String."

My code is below. Appreciate any and all help! Thanks.

            def hello
            word_bank = ["hello", "hi", "howdy"]
            print "Say a word: "
            greeting = $stdin.gets.chomp.to_s

            if greeting.include?(word_bank[0..2])
               puts "success!"
              else
                puts "failure."
              end

            end

            hello

Upvotes: 1

Views: 113

Answers (2)

Ursus
Ursus

Reputation: 30056

include? is an array's method.

word_bank = ["hello", "hi", "howdy"]
print "Say a word: "
greeting = gets.chomp

if word_bank.include?(greeting)
  puts "success!"
else
  puts "failure."
end

puts [1,2,3].include?(1) # true
puts [1,2,3].include?(4) # false

If word_bank was big, for performance reason we should use a set instead of an array.

require 'set'

word_bank = Set.new(["hello", "hi", "howdy"])

Upvotes: 3

bork
bork

Reputation: 1674

This is how I'd solve the issue, I haven't tested it though but it should work.

def hello
  word_bank = ['hello', 'hi', 'howdy']
  print 'Say a word: '
  greeting = $stdin.gets.chomp.to_s

    word_bank.each do |w|

    w == greeting ? (puts 'success') : (puts 'failure')

  end   
end

Upvotes: 0

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