CODEWITHSUNDEEP
batch-filebatch-processing
George Hovhannisian
George Hovhannisian

Reputation: 707

batch - Directory of the currently processed file in batch

I'm trying to use an unpacker to extract multiple files. My script goes like this

for /R %%i in (*.ext) DO quickbms.exe -o script.bms "%%i" "%%~ni"

The problem is when I drop a file from C:\archives it extracts all files to that directory, including the archives in C:\archives\dir1, C:\archives\dir2, etc.

How do I extract all archives in their own folder without having to manually start the script in each folder?

Upvotes: 2

Views: 2059

Answers (1)

JosefZ
JosefZ

Reputation: 30113

for /R %%i in (*.ext) DO quickbms.exe -o script.bms "%%~i" "%%~dpni"

Please read for /?: The modifiers can be combined to get compound results.

By Command Line arguments (Parameters):

  • …
  • %~f1 Expand %1 to a Fully qualified path name - C:\utils\MyFile.txt
  • %~d1 Expand %1 to a Drive letter only - C:
  • %~p1 Expand %1 to a Path only e.g. \utils\ this includes a trailing \ which will be interpreted as an escape character by some commands.
  • %~n1 Expand %1 to a file Name without file extension C:\utils\MyFile or if only a path is present (with no trailing backslash) - the last folder in that path.
  • …

Your "%%~pi\%%~ni" would result (in terms of above examples) to \utils\\MyFile.txt (note two consecutive \\ reverse solidi).
Fortunately, batch interpreter considers doubled \\ (and even multipled) backslash in a path as a single \ reverse solidus…

Upvotes: 3

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