CODEWITHSUNDEEP
linuxbashawksed
Luca
Luca

Reputation: 41

BASH exclude specific char from string

I must implement one script, i should get list of virtual hosts apache:

apachectl -S | grep -i site | awk '{print $5}'

output:

Syntax OK
(/usr/local/apache2/conf/site.conf:1)

how can i receive this output? (without Syntax OK/()/:*):

/usr/local/apache2/conf/site.conf

Upvotes: 0

Views: 548

Answers (3)

Ed Morton
Ed Morton

Reputation: 204239

The Syntax OK text must be going to stderr, it's not going to stdout or it'd get filtered out by the grep/awk. Try this:

apachectl -S 2>&1 | awk '$5~/site/{gsub(/^\(|:[^:]+\)$/,"",$5); print $5}'

Upvotes: 1

BOC
BOC

Reputation: 1139

Using a regular expression to capture from the opening parenthesis to the ":"

apachectl -S 2>&1 | perl -ne '/\((.*site.*):/i && {print $1}'

Upvotes: 0

heemayl
heemayl

Reputation: 42107

With awk setting (, ) and : as field separators, and getting the second field:

awk -F'[():]' '{print $2}'

Example:

% awk -F'[():]' '{print $2}' <<<'Syntax OK (/usr/local/apache2/conf/site.conf:1)'
/usr/local/apache2/conf/site.conf

Upvotes: 1

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