Reputation: 4787
I am using Python 3.5, PyQt5 on OSX and I was wondering if there was a possibility to update the QProgressBar without slowing down the whole computing work. Here was my code and if I did just the task without the progressbar update it was soo much faster!!
from PyQt5.QtWidgets import (QWidget, QProgressBar, QPushButton, QApplication)
from jellyfish import levenshtein_distance, jaro_winkler
import sys
class Example(QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
self.pbar = QProgressBar(self)
self.pbar.setGeometry(30, 40, 200, 25)
self.btn = QPushButton('Start', self)
self.btn.move(40, 80)
self.btn.clicked.connect(self.doAction)
self.setGeometry(300, 300, 280, 170)
self.show()
def doAction(self):
#setup variables
step = 0
m = 1000
n = 500
step_val = 100 / (m * n)
#make task
for i in range(m):
for j in range(n):
jaro_winkler(str(i), str(j))
#show task
print(i,j)
#update progressbar
step += step_val
self.pbar.setValue(step)
QApplication.processEvents()
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
Then with help from stackoverflow users I got the hint to make a separate working thread and connect the updating signal to the GUI. I did it and it looks now like the following code. It also works and is much faster, but I can't figure out how to connect the emited signal to the GUI. Can somebody please help me? Many thanks in advance!
from jellyfish import jaro_winkler
from PyQt5 import QtCore
from PyQt5.QtWidgets import QApplication, QWidget, QPushButton, QProgressBar, QMainWindow
import time
import numpy as np
class Main_Window(QMainWindow):
def __init__(self):
super(Main_Window,self).__init__()
self.initUI()
def initUI(self):
self.pbar = QProgressBar(self)
self.pbar.setGeometry(30, 40, 200, 25)
self.btn = QPushButton('Start', self)
self.btn.move(40, 80)
self.btn.clicked.connect(MyThread.doAction)
self.setGeometry(300, 300, 280, 170)
self.show()
def updateProgressBar(self, val):
self.pbar.setValue.connect(val)
class MySignal(QWidget):
pbar_signal = QtCore.pyqtSignal(int)
class MyThread(QtCore.QThread):
def __init__(self):
super().__init__()
def doAction(self):
t = time.time() #for time measurement
#setup variables
step = 0
m = 1000
n = 500
pbar_val = 100 / m
signal_instance = MySignal()
#make task
for i in range(m):
for j in range(n):
jaro_winkler(str(i), str(j))
signal_instance.pbar_signal.emit(pbar_val)
#measuring task time
print(np.round_(time.time() - t, 3), 'sec elapsed')
if __name__ == '__main__':
import sys
app = QApplication(sys.argv)
w = Main_Window()
sys.exit(app.exec_())
Upvotes: 1
Views: 2297
Reputation: 120578
There are three things slowing the code down:
print(i,j)
roughly halves the time doAction
takes to run.processEvents
500,000 times. Commenting out QApplication.processEvents()
reduces the run time by another two-thirds.self.pbar.setValue(step)
halves the time again.Hopefully it should be obvious by now that attempting to update the gui 500,000 times during a task that should take less than a second is massive overkill! Most user's reaction times are about 200ms at best, so you only need to update the gui about once every 100ms.
Given that, one simple fix is to move the updates into the outer loop:
for i in range(m):
for j in range(n):
jaro_winkler(str(i), str(j))
# show task
# print(i,j)
step += step_val
# update progressbar
self.pbar.setValue(step)
QApplication.processEvents()
But an even better solution would be to move the calculations into a separate worker thread and have it periodically emit a custom signal to update the progress bar:
class Main_Window(QMainWindow):
...
def initUI(self):
...
self.btn.clicked.connect(self.doAction)
self.thread = MyThread()
self.thread.pbar_signal.connect(self.pbar.setValue)
def doAction(self):
if not self.thread.isRunning():
self.thread.start()
class MyThread(QtCore.QThread):
pbar_signal = QtCore.pyqtSignal(int)
def run(self):
#for time measurement
t = time.time()
#setup variables
m = 1000
n = 500
progress = step = 100 / m
#make task
for i in range(m):
for j in range(n):
jaro_winkler(str(i), str(j))
progress += step
self.pbar_signal.emit(progress)
#measuring task time
print(np.round_(time.time() - t, 3), 'sec elapsed')
Upvotes: 2