Reputation: 2697
Suppose I have the following tables:
user_current_value_stats
id user_id current_total_value
1 12 175
2 14 125
3 17 170
4 18 115
value_awarded_stats_history
id user_id value_awarded date
1 12 55 2016-10-5 00:00:00+05:30
2 14 50 2016-10-5 00:00:00+05:35
3 17 70 2016-10-5 00:00:00+06:35
4 18 40 2016-10-5 00:00:00+07:34
5 12 50 2016-10-11 00:00:00+04:30
6 14 65 2016-10-11 00:00:00+04:40
7 17 75 2016-10-11 00:00:00+05:40
8 18 -35 2016-10-11 00:00:00+06:40
9 12 30 2016-10-12 00:00:00+04:30
10 14 65 2016-10-12 00:00:00+04:40
11 17 35 2016-10-12 00:00:00+05:40
12 18 65 2016-10-12 00:00:00+06:40
13 12 40 2016-10-13 00:00:00+04:40
14 14 -55 2016-10-13 00:00:00+05:40
15 17 -10 2016-10-13 00:00:00+05:45
16 18 45 2016-10-13 00:00:00+06:40
Expected Result
id user_id current_total_value last_week_value difference
1 12 175 130 45
2 14 125 140 -15
3 17 170 180 -10
4 18 115 70 45
I need to
user_current_value_stats
value_awarded_stats_history
for the last week as last_week_value
(date will be given)last_week_value
and current_total_value
as differenceThe result should have the following columns id, user_id, current_total_value, last_week_value, difference.
(Also current_total_value
can also be got as aggregate of all the value_awarded
for the particular user. The column value_awarded
is actually redundant data and is the sum of value_awarded
for from value_awarded_stats_history
for that user.)
Upvotes: 0
Views: 143
Reputation: 394
You have to use a subquery to calculate the last_week_value :
select v.user_id, sum(v.value_awarded) as last_week_value
from value_awarded_stats_history v
where v.date > (current_date - '1 week')
group by v.user_id
So the complete query would be something like this:
select t1.id
, t1.user_id
, t1.current_total_value
, t2.last_week_value
, (t1.current_total_value - t2.last_week_value) as difference
from user_current_value_stats t1
left outer join
(select v.user_id, sum(v.value_awarded) as last_week_value
from value_awarded_stats_history v
where v.date > (current_date - '1 week')
group by v.user_id) t2 on t2.user_id = t1.user_id
Upvotes: 1