Reputation: 2949
I have two xts
objects of different lengths in R
, defined as:
library(xts)
seq <- seq(as.POSIXct("2015-09-01"),as.POSIXct("2015-09-02"), by = "1 hour")
ob1 <- xts(data.frame(val=1:(length(seq))),seq)
seq2 <- seq(as.POSIXct("2015-09-01"),as.POSIXct("2015-09-03"), by = "1 hour")
ob2 <- xts(data.frame(val=1:(length(seq2))),seq2)
Now when I perform addition over ob1
and ob2
as
ob1 + ob2
I get the result, but the addition is done over the timestamps which are common in both. Is there a way where I can retain all the distinct timestamps of both the objects and still get the result?
Upvotes: 0
Views: 117
Reputation: 2100
Not the prettiest solution, but from the top of my head...
test<-merge(ob1,ob2)
test<-xts(rowSums(test, na.rm=T), order.by = time(test))
Upvotes: 0