CODEWITHSUNDEEP
regexnotepad++
Michael Albertson
Michael Albertson

Reputation: 1

How to remove everything outside of round brackets in notepad++

I am trying to extract image urls from css file using a notepad++. Since all the image urls are inside of the round brackets I am thinking about regex to remove everything before ( and everything after ). Here is a text example :

    text-transform:uppercase;

    font-size:17px;

}

.conTxt .btnGiveAccess{

    width:532px;

    height:145px;

    background:url(http://www.website.com/css/images/btn-give-me-access2.jpg) no-repeat center top;

    margin:0 auto;

    display:block;

}

.conTxt .btnGiveAccess:hover{

    background:url(http://www.website.com/css/images/btn-give-me-access2.jpg) no-repeat center -145px;

}

/*#########################################*/
popup window
/*#########################################*/
/*a {

As a result I woul dlike to get the following:

http://www.website.com/css/images/btn-give-me-access2.jpg

http://www.website.com/css/images/btn-give-me-access2.jpg

I also tried the following regex to delete everything before http:// 

^[^http]*`  Also .*((.*)).*

but it didnt work. Could anybody please help?

Upvotes: 0

Views: 3575

Answers (2)

AdrianHHH
AdrianHHH

Reputation: 14047

For the given text the following works. Use a find text of (\A|\))([^()]*)(\(|\Z) and replace that with \r\n. This will leave the required text plus a few empty lines that can easily be removed, eg by menu => Edit => Line operations => Remove empty lines.

A minor variation is to use a replacement string of \1\3. which will remove everything outside the round brackets leaving the brackets themselves and the text between them. It is then a simple job to remove all round brackets, perhaps replacing them with new lines. This could be done with a find text of [()]+ and replace string of \r\n.

Explanation of the first regular expression. The captures are:

  1. (\A|\)) which looks for either the start of the buffer, the \A or a close bracket.
  2. ([^()]*) which looks for a sequence of characters that do not include round brackets.
  3. (\(|\Z) which looks for a close bracket or the end of the buffer, the \Z.

The effect is to look for a three types of text.

  1. From start of buffer to first opening round bracket. This matches (\A)([^()]*)(\(|\Z).
  2. From close bracket to open bracket. This matches (\))([^()]*)(\().
  3. From close bracket to end of buffer. This matches (\))([^()]*)(\Z).

This may not do the desired job if there are nested round brackets, but the question does not specify what should happen in such cases.

Upvotes: 1

cco
cco

Reputation: 6281

If none of the URLs have parens in them, you could use \((.*)\)

The difference between this and what you show above is that the outer () (the literal ones, not the ones that make the regex capture) are escaped using \

Upvotes: 0

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