CODEWITHSUNDEEP
rubyregexsplit
Apeiron
Apeiron

Reputation: 704

ruby regex split difficulties, close but not quite

I am having quite the difficulty using regex in ruby to split a string along several delimiters these delimiters are:

each of these delimiters can have any amount of white space on either side of the delimiter but each item can contain a valid space. a great example that I've been testing against is the string 1, 2 /3 and 4 12

what I would like is something around the lines of "1, 2 /3 and 4 12".split(regex) =>["1", "2", "3", "4 12"]

The closest I've been able to get is /\s*,|\/|&|and \s*/ but this generates ["1", " 2 ", "3 ", "4 12"] instead of the desired results.

Realize this is very close and I could simply all trim on each item, but being so close and knowing it can be done is sort of driving me mad. Hopefully someone can help me keep the madness at bay.

Upvotes: 3

Views: 358

Answers (3)

tinifni
tinifni

Reputation: 2392

You can try:

(?:\s*)[,\/](?:\s*)|(?:\s*)and(?:\s*)

But as Nakilon suggested, you may have better luck with scan instead of split.

Upvotes: 1

Nakilon
Nakilon

Reputation: 35064

Try .scan:

irb(main):030:0> "1, 2 /3 and 4 12".scan(/\d+(?:\s*\d+)*/)
=> ["1", "2", "3", "4 12"]

Upvotes: 1

sepp2k
sepp2k

Reputation: 370112

/\s*,|\/|&|and \s*/

This parses as /(\s*,)|\/|&|(and \s*)/. I.e. the leading \s* only applies to the comma and the trailing \s* only applies to "and". You want:

/\s*(,|\/|&|and )\s*/

Or, to avoid capturing:

/\s*(?:,|\/|&|and )\s*/

Upvotes: 3

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