Reputation: 1093
I know this may have been asked before, but I can't find anything that quite matches my specific requirements.
I'm loading a page on a local Linux server, when it loads I need to know does the server it is running on have Internet Access and is DNS resolving.
I've got this working, BUT... if there is no Internet connection the page takes a very long time to load, if there is a connection then it loads instantly.
I'm using the following to check for Internet Access:
$check1 = checkState('google-public-dns-a.google.com',53);
$check2 = checkState('resolver1.opendns.com',53);
if ($check1 == "YES" || $check2 == "YES"){
echo "Internet Available";
}
function checkState($site, $port) {
$state = array("NO", "YES");
$fp = @fsockopen($site, $port, $errno, $errstr, 2);
if (!$fp) {
return $state[0];
} else {
return $state[1];
}
}
and checking DNS resolution using:
$nameToIP = gethostbyname('www.google.com');
if (preg_match('/^\d/', $nameToIP) === 1) {
echo "DNS Resolves";
}
Can anyone recommend a better way ? so if there is no connection the page doesn't stall for a long time.
Thanks
Upvotes: 0
Views: 2562
Reputation: 7080
You can use fsockopen
Following example works well and tells you whether you are connected to internet or not
function is_connected() {
$connected = @fsockopen("www.google.com", 80); //website, port (try 80 or 443)
if ($connected){
fclose($connected);
return true;
}
return false;
}
Reference : https://stackoverflow.com/a/4860432/2975952
Check DNS
resolves here
function is_site_alive(){
$response = null;
system("ping -c 1 google.com", $response);
if($response == 0){
return true;
}
return false;
}
Reference : https://stackoverflow.com/a/4860429/2975952
Upvotes: 2