CODEWITHSUNDEEP
spring-bootthymeleaf
kamaci
kamaci

Reputation: 75137

Thymeleaf Modify and Post Current Object

I have a form and post data into controller via Thymeleaf:

<form action="lia.html" th:action="@{/lia}" th:object="${myRequest}" method="post">

At another place of my html page, if a user click a particular button, I want to modify that object and send it to same controller.

I have already that object which has been initialised. Button is not a part of any form. How can I send that object into a controller with Thymeleaf.

PS: I know that I can send it via Javascript or put such buttons into a form but I want to learn the Thymeleaf way.

Upvotes: 9

Views: 3424

Answers (1)

Pau
Pau

Reputation: 16106

I think the only similar approach to what you're looking for is using bind with Spring EL expressions.

Thanks to the advanced form-field binding capabilities in Spring MVC, we can use complex Spring EL expressions to bind dynamic form fields to our form-backing bean. This will allow us to create new Row objects in our SeedStarter bean, and to add those rows’ fields to our form at user request.

Take a look the next link, where is good example:

http://www.thymeleaf.org/doc/tutorials/2.1/thymeleafspring.html#dynamic-fields

  • The button

    <button type="submit" name="removeRow" 
            th:value="${rowStat.index}" th:text="#{seedstarter.row.remove}">Remove row</button>

  • Request Mapping

    @RequestMapping(value="/seedstartermng", params={"removeRow"})
public String removeRow(
    final SeedStarter seedStarter, final BindingResult bindingResult, 
    final HttpServletRequest req) {

    final Integer rowId = Integer.valueOf(req.getParameter("removeRow"));
seedStarter.getRows().remove(rowId.intValue());
    return "seedstartermng";
}

Upvotes: 1

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