CODEWITHSUNDEEP
phprubyregex
Forwarding
Forwarding

Reputation: 245

How can I replace all instances of a match with itself and more? Ruby

Ok, so say I have a bunch of inputs in an HTML file like this:

<input class="form-control" type="text" id="ogwb">
<input class="form-control" type="text" id="aosgh">
<input class="form-control" type="text" id="aghw">

How can I replace all instances of the ids with themselves and a name and value attribute having the same id value like so:

<input class="form-control" type="text" id="ogwb" name="ogwb" value="<?php echo htmlspecialchars($_POST['ogwb']); ?>">
<input class="form-control" type="text" id="aosgh" name="aosgh" value="<?php echo htmlspecialchars($_POST['aosgh']); ?>">
<input class="form-control" type="text" id="aghw" name="aghw" value="<?php echo htmlspecialchars($_POST['aghw']); ?>">

This is what I've tried:

f = File.read('my.html')
$arr = f.scan(/id="([^"]*)"/)

$arr.each{ |a|
    e_ = a.join(", ")+'"'
    e__ = a.join(", ")+'"'+' name="'+a.join(", ")+'" value="<?php echo htmlspecialchars($_POST['+"'"+a.join(", ")+"'"+']); ?>"'
    f.gsub(/#{e_}/,e__)
}

Which if I do puts e_ and puts e__ I get the match and replace I want, but gsub doesn't seem to work.

Upvotes: 0

Views: 51

Answers (1)

Addison
Addison

Reputation: 8377

You will want to use regex to grab this:

<input class="form-control" type="text" id="([^"]+)">

Notice that I surrounded the text value of the id with a capturing group (the brackets). This is capture group #1.

You can access the first captured group with \1.

So you'll want to search for the previous regex, and replace it with the following:

<input class="form-control" type="text" id="\1" name="\1" value="<?php echo htmlspecialchars($_POST['\1']); ?>">

Demonstration: https://regex101.com/r/qeHkmg/1

Documentation: http://www.regular-expressions.info/replacebackref.html

Upvotes: 1

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