CODEWITHSUNDEEP
javamathlibgdx
user4822216
user4822216

Reputation:

How to create a random boolean with chances?

I saw the libgdx MathUtils.randomBoolean(chances), I guess this would help me but I'm not sure.

MathUtils.randomBoolean(10); // I'm not sure if this will give 10% chance?

Upvotes: 0

Views: 1214

Answers (2)

Andrew Li
Andrew Li

Reputation: 57964

Take a look at the LibGDX Javadocs regarding MathUtils:

randomBoolean

public static boolean randomBoolean(float chance)

Returns true if a random value between 0 and 1 is less than the specified value.

That means if you specify a number (passed as an argument), the method will return true if the randomly generated number (between 0 and 1) is less than the passed chance. In this case it would be:

MathUtils.randomBoolean(0.1);

This is because 0.1 is 10%, or 10/100. Thus, a random number between 0 and 1, if less than 0.1, will cause the method to return true.

Your code previously would always return true because a number between 0 and 1 is always less than 10.

Upvotes: 3

Zbynek Vyskovsky - kvr000
Zbynek Vyskovsky - kvr000

Reputation: 18855

MathUtils.randomBoolean(float chance) gives the true with probability given by the parameter. But the parameter chance can take value between 0 - 1, meaning that for example 0.1 gives 10% (0.1) probability of returning true.

Your example - 10 - would always result in true as it's bigger than 1.

Upvotes: 5

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