Reputation: 31284
I am doing some image processing, and I need to check if a binary image is identical to another.
Processing speed isn't an issue, and the simple thing I thought to do was count the white pixels remaining after adding the inverse of image A to image B (these images are very nearly identical, but not quite--some sort of distance metric is the goal).
However, in order to create the composite image, I need to include a "mask" that is the same size as the two images.
I am having trouble finding an example of creating the mask online and using it for the Image.composite function.
Here is my code:
compA = ImageOps.invert(imgA)
imgAB = Image.composite(compA,imgB,??? mask)
Right now, I have created a mask of all zeros--however, the composite image does not appear correctly (both A and B are exactly the same images; a mask of all zeros--or all ones for that matter--does not work).
mask = Image.fromarray(np.zeros(imgA.size,dtype=int),mode='L')
imgAB = Image.composite(compA,imgB,mask)
How do I just add these two binary images on top of eachother?
Upvotes: 0
Views: 1329
Reputation: 15369
Clearly you're using numpy
, so why not just work with numpy
arrays and explicitly do whatever arithmetic you want to do in that domain—such as subtracting one image from the other:
arrayA = numpy.asarray( imgA, dtype=int )
arrayB = numpy.asarray( imgB, dtype=int )
arrayDelta = arrayA - arrayB
print( (arrayDelta !=0 ).sum() ) # print the number of non-identical pixels (why count them by hand?)
# NB: this number may be inflated by a factor of 3 if there are 3 identical channels R, G, B
imgDelta = Image.fromarray((numpy.sign(arrayDelta)*127+127).astype('uint8')) # display this image if you want to visualize where the differences are
You could do this even more simply, e.g.
print((numpy.asarray(imgA) != numpy.asarray(imgB)).sum())
but I thought casting to a signed integer type first and then subtracting would allow you to visualize more information (A white and B black -> white pixel in delta; A black and B white -> black pixel in delta)
Upvotes: 1