Reputation: 1506
I have read the post grep all characters including newline but I not working with XML so it's a bit different with my Linux command.
I have the following data:
Example line 0</span>
<tag>Example line 1</tag>
<span>Example line 1.5</span>
<tag>
Example line 2
</tag>
Example line 3
<span>Example line 4</span>
Using this command cat file.txt | grep -o '<tag.*tag>\|^--.*'
I get:
<tag>Example line 1</tag>
However, I want the output to be:
<tag>Example line 1</tag>
<tag>Example line 2</tag>
How can I match anything between the strings, including the newline?
Note: I need to used <tag
and tag>
as strings because other files can contain multiple tags and text in between the lines. Will update sample data to show that.
Upvotes: 2
Views: 826
Reputation: 113814
Consider this test file:
$ cat file2
Example line 0</span>
<tag>Example line 1</tag>
<span>Example line 1.5</span>
<tag>
Example line 2
</tag>
Example line 3
<span>Example line 4</span>
This produces the output that you want (requires GNU sed):
$ sed -z 's|\n||g; s|</tag>|&\n|g; s|[^\n]*<tag>|<tag>|; s|\n[^\n]*<tag>|\n<tag>|g; s|\n[^\n]*$|\n|' file2
<tag>Example line 1</tag>
<tag>Example line 2</tag>
Limitation: Note that processing XML-like text with non-specialized tools can be quite fragile.
Upvotes: 0
Reputation: 784898
This is easier done with gnu-awk
using </tag>
as record separator:
awk -v RS='</tag>' 'RT {gsub(/\n/, ""); print $0 RT}' file
<tag>Example line 1</tag>
<tag>Example line 2</tag>
Upvotes: 2