CODEWITHSUNDEEP
c++pythonswig
Gennadiy Rozental
Gennadiy Rozental

Reputation: 1945

Python Swig wrapper: how access underlying PyObject

I've got class A wrapped with method foo implemented using %extend:

class A { ... %extend { void foo() { self->foo_impl(); } }

Now I want to increase ref count to an A inside foo_impl, but I only got A* (as self).

Question: how can I write/wrap function foo, so that I have an access both to A* and underlying PyObject*?

Thank you

Upvotes: 1

Views: 712

Answers (1)

Steve
Steve

Reputation: 8293

I think it's not possible. If you need to increase the refcount, it's because you don't want the C++ object to be destroyed when it goes out of scope because there is a pointer to that object elsewhere. In that case, look at using the DISOWN typemap to ensure the target language doesn't think it "owns" the C++ object, so it won't get destroyed.

Upvotes: 1

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