Reputation: 434
Here is an extern
and a static
variable with same name. The output prints the static variable a=10. Why is there no syntax error and how would I access extern a
if needed?
#include<stdio.h>
extern int a;
static int a=10;
main()
{
printf("%d\n",a);
}
Upvotes: 0
Views: 263
Reputation: 32576
The C standard allows the opposite, extern
after static
:
6.2.2 Linkages of identifiers
....
3 If the declaration of a file scope identifier for an object or a function contains the storage-class specifierstatic
, the identifier has internal linkage.4 For an identifier declared with the storage-class specifier
extern
in a scope in which a prior declaration of that identifier is visible, if the prior declaration specifies internal or external linkage, the linkage of the identifier at the later declaration is the same as the linkage specified at the prior declaration. If no prior declaration is visible, or if the prior declaration specifies no linkage, then the identifier has external linkage.
At the same time it states:
7 If, within a translation unit, the same identifier appears with both internal and external linkage, the behavior is undefined.
BTW, the C++ standard makes it explicit:
7.1.1 Storage class specifiers
....static int b; // b has internal linkage extern int b; // b still has internal linkage
....
extern int d; // d has external linkage static int d; // error: inconsistent linkage
Upvotes: 2