CODEWITHSUNDEEP
c++qtqsortqlist
fyngyrz
fyngyrz

Reputation: 2658

Qt 4.8: trying to sort QList<QStringList> on 1st element of QStringList as integer

I have a QList<QStringList> named sortme of which the first QString in each QStringList is a valid integer as a string, for example:

exampleQStringList << "5" << "foo" << "bar"

For qsort, which is what 4.8 uses rather than std:, I understand I want a comparison function. Here's what I thought I needed to write:

bool MainWindow::qslLessThan(const QList<QStringList> &v1, const QList<QStringList> &v2)
{
    // here I would get the first element.toInt() and return <
    return(true);
}

and then:

qSort(sortme.begin(), sortme.end(), qslLessThan);

I am missing something, clearly, as the compiler complains "error: no matching function for call to 'qSort(QList::iterator, QList::iterator, )'" even though I am trying to sort a QList<QStringList> and sortme is that.

Upvotes: 0

Views: 2283

Answers (1)

aatwo
aatwo

Reputation: 1008

Firstly the function that the qsort() requires must be a raw function and not a member of any class. Secondly this comparison function must take, in your case, QStringList references rather than QList references as it is the QStringLists you are comparing.

#include <QCoreApplication>
#include <QDebug>

bool lessThan( const QStringList& v1, const QStringList& v2 )
{
    return v1.first() < v2.first();
}

int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);

    QList<QStringList> sortme;

    QStringList entryOne    = QStringList() << "1" << "foo1" << "bar1";
    QStringList entryTwo    = QStringList() << "2" << "foo2" << "bar2";
    QStringList entryThree  = QStringList() << "3" << "foo3" << "bar3";

    sortme << entryTwo << entryOne << entryThree;

    qSort( sortme.begin(), sortme.end(), lessThan );

    // Print out the list data so we can see that it got sorted ok
    for( int i = 0; i < sortme.size(); i++ )
    {
        QString data = sortme.at( i ).join( "," );
        qDebug() << QString( "Item %1: %2" ).arg( i + 1 ).arg( data );
    }

    return a.exec();
}

Upvotes: 3

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