CODEWITHSUNDEEP
pythonhtmldjango
Keith
Keith

Reputation: 797

urls.py entry for django v1.10 mysite.com:8000/index.html

I'm having trouble getting the url entry in my app's urls.py file how I want it. When a person enters mysite.com:8000/, I want it to use the same view as mysite.com:8000/index.html I can use url(r'^index.html$', views.index, name='index'), and the view is properly displayed when I type mysite.com:8000/index.html into the chrome address bar, or I can trim the .htmloff both the urls.py entry and the address bar and it's ok, but I figured with regex, I could get this to display for / or for index*

lots of googling hasn't let me to an answer yet...

EDIT: update based on @moses:

from django.conf import settings
from django.conf.urls import url
from django.conf.urls.static import static
from . import views

urlpatterns = [
        url(r'^(index\.?[html]{,4})?$', views.index, name='index'),
#       url(r'^index$', views.index, name='index'),
] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)

now I get: "Exception Value:index() takes exactly 1 argument (2 given)"

Upvotes: 1

Views: 87

Answers (1)

Moses Koledoye
Moses Koledoye

Reputation: 78564

You can use the following regex pattern that matches 0 or 1 repetitions of 'index.html' in the url i.e. either ^$ or r'^index.html$':

>>> re.match(r'^(?:index\.html)?$', 'index.html')
<_sre.SRE_Match object; span=(0, 10), match='index.html'>
>>> re.match(r'^(?:index\.html)?$', '')
<_sre.SRE_Match object; span=(0, 0), match=''>
>>> re.match(r'^(?:index\.html)?$', 'login')
>>>

And your Django url pattern becomes:

url(r'^(?:index.html)?$', views.index, name='index')

See demo: https://regex101.com/r/MVCPDN/2

Upvotes: 1

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