CODEWITHSUNDEEP
phpregexpreg-replacesubstr
Max
Max

Reputation: 116

substr() to preg_replace() matches php

I have two functions in PHP, trimmer($string,$number) and toUrl($string). I want to trim the urls extracted with toUrl(), to 20 characters for example. from https://www.youtube.com/watch?v=HU3GZTNIZ6M to https://www.youtube.com/wa...

function trimmer($string,$number) {
    $string = substr ($string, 0, $number);
    return $string."...";
}

function toUrl($string) {
    $regex="/[^\W ]+[^\s]+[.]+[^\" ]+[^\W ]+/i";
    $string= preg_replace($regex, "<a href='\\0'>".trimmer("\\0",20)."</a>",$string);
    return $string;    
}

But the problem is that the value of the match return \\0 not a variable like $url which could be easily trimmed with the function trimmer().

The Question is how do I apply substr() to \\0 something like this substr("\\0",0,20)?

Upvotes: 3

Views: 472

Answers (1)

Johnny
Johnny

Reputation: 1798

What you want is preg_replace_callback:

function _toUrl_callback($m) {
  return "<a href=\"" . $m[0] . "\">" . trimmer($m[0], 20)  ."</a>";
}
function toUrl($string) {
  $regex = "/[^\W ]+[^\s]+[.]+[^\" ]+[^\W ]+/i";
  $string = preg_replace_callback($regex, "_toUrl_callback", $string);
  return $string;
}

Also note that (side notes wrt your question):

  1. You have a syntax error, '$regex' is not going to work (they don't replace var names in single-quoted strings)
  2. You may want to look for better regexps to match URLs, you'll find plenty of them with a quick search
  3. You may want to run through htmlspecialchars() your matches (mainly problems with "&", but that depends how you escape the rest of the string.

EDIT: Made it more PHP 4 friendly, requested by the asker.

Upvotes: 2

Related Questions