CODEWITHSUNDEEP
swiftoption-typeguard
serdar aylanc
serdar aylanc

Reputation: 1347

swift - unwrapping optional with "guard let"

I am parsing JSON data. After I start getting unexpectedly found nil while unwrapping an Optional value errors. I tried to use guard statement.

But again I am getting the same error.

guard let articleTitle = self.articles?[indexPath.row]["title"].string! else {return}

I simulate nil value like this:

guard let articleTitle = self.articles?[indexPath.row]["t"].string! else {return}

What I am doing wrong?

Upvotes: 1

Views: 2260

Answers (1)

idmean
idmean

Reputation: 14865

It doesn’t make much sense to force unwrap the optional in a conditional let assingment. Remove the !:

guard let articleTitle = self.articles?[indexPath.row]["title"].string else {return}

Otherwise the right-hand side will never produce nil but crash.

Upvotes: 3

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