PHP: Check if variable exist but also if has a value equal to something

Question

I have (or not) a variable $_GET['myvar'] coming from my query string and I want to check if this variable exists and also if the value corresponds to something inside my if statement:

What I'm doing and think is not the best way to do:

if(isset($_GET['myvar']) && $_GET['myvar'] == 'something'): do something

My question is, exist any way to do this without declare the variable twice?

That is a simple case but imagine have to compare many of this $myvar variables.

Answer 1

I am not a expert in PHP but I believe my solution may work since it worked for me and I will do this with a code I used just recently.

This is what I did and the logic.

1. Using Isset I check to see if it had anything
2. Used the forLoop to circle through the values
3. As it circles check to see if the values equals to something I wanted!
4. Tested it and yes it works

<?php
if (isset($_POST['growgroups'])) {
    echo '<h3>You have select the following grow groups</h3>';
    foreach ($_POST['growgroups'] as $growgroups) {
        echo '<p>' . $growgroups . '</p>';
        if ($growgroups === 'Fervent Foodies') {
            echo '<p>Great Choice!</p>';
        } 
        if ($growgroups === 'The Conversation') {
            echo '<p>Enjoy the converation!</p>';
        } 
    }
}

Answer 2

As of PHP7 you can use the Null Coalescing Operator ?? to avoid the double reference:

// $_GET['myvar'] isn't set...
echo ($_GET['myvar'] ?? '') == 'hello' ? "hello!\n" : "goodbye!\n";

// $_GET['myvar'] is set but != 'hello'
$_GET['myvar'] = 'farewell';
echo ($_GET['myvar'] ?? '') == 'hello' ? "hello!\n" : "goodbye!\n";

// $_GET['myvar'] is set and == 'hello'
$_GET['myvar'] = 'hello';
echo ($_GET['myvar'] ?? '') == 'hello' ? "hello!\n" : "goodbye!\n";

Output:

goodbye!
goodbye!
hello!

Code demo on 3v4l.org

In general, the expression

$a ?? $b

is equivalent to

isset($a) ? $a : $b

Note that in the code example it is necessary to place parentheses around $_GET['myvar'] ?? '' as == has higher precedence than ?? and thus

$_GET['myvar'] ?? '' == 'hello'

would evaluate to:

$_GET['myvar'] ?? ('' == 'hello')

which would be true as long as $_GET['myvar'] was set and "truthy" (see the manual) and false otherwise (since '' == 'hello' is false).

Precedence code demo on 3v4l.org

Answer 3

If you're looking for a one-liner to check the value of a variable you're not sure is set yet, this works:

if ((isset($variable) ? $variable : null) == $value) { }

The only possible downside is that if you're testing for true/false - null will be interpreted as equal to false.

Answer 4

This is similar to the accepted answer, but uses in_array instead. I prefer to use empty() in this situation. I also suggest using the new shorthand array declaration which is available in PHP 5.4.0+.

$allowed = ["something","nothing"];
if(!empty($_GET['myvar']) && in_array($_GET['myvar'],$allowed)){..}

Here is a function for checking multiple values at once.

$arrKeys = array_keys($_GET);
$allowed = ["something","nothing"];

function checkGet($arrKeys,$allowed) { 
    foreach($arrKeys as $key ) {
        if(in_array($_GET[$key],$allowed)) {
            $values[$key];
        }
    }
    return $values;
}

Answer 5

<?php

function myset(&$var,$value=false){
    if(isset($var)):
        return $var == $value ? $value : false;
    endif;
    return false;
}

$array['key'] = 'foo';

var_dump(myset($array['key'],'bar')); //bool(false)

var_dump(myset($array['key'],'foo'));//string(3) "foo"

var_dump(myset($array['baz'],'bar'));//bool(false) 

Answer 6

No official reference but it worked when I tried this:

if (isset($_GET['myvar']) == 'something')

Answer 7

A solution that I have found from playing around is to do:

if($x=&$_GET["myvar"] == "something")
{
    // do stuff with $x
}

Answer 8

I use all time own useful function exst() which automatically declare variables.

Example -

$element1 = exst($arr["key1"]);
$val2 = exst($_POST["key2"], 'novalue');


/** 
 * Function exst() - Checks if the variable has been set 
 * (copy/paste it in any place of your code)
 * 
 * If the variable is set and not empty returns the variable (no transformation)
 * If the variable is not set or empty, returns the $default value
 *
 * @param  mixed $var
 * @param  mixed $default
 * 
 * @return mixed 
 */

function exst( & $var, $default = "")
{
    $t = "";
    if ( !isset($var)  || !$var ) {
        if (isset($default) && $default != "") $t = $default;
    }
    else  {  
        $t = $var;
    }
    if (is_string($t)) $t = trim($t);
    return $t;
}

Answer 9

why not create a function for doing this, convert the variable your want to check into a real variable, ex.

function _FX($name) { 
  if (isset($$name)) return $$name;
  else return null; 
}

then you do _FX('param') == '123', just a thought

Answer 10

As mellowsoon suggest, you might consider this approach:

required = array('myvar' => "defaultValue1", 'foo' => "value2", 'bar' => "value3", 'baz' => "value4");
$missing = array_diff($required, array_keys($_GET));
foreach($missing as $key => $default  ) {
    $_GET[$key] = $default  ;
}

You put the default values and set the not recieved parameters to a default value :)

Answer 11

Thanks Mellowsoon and Pekka, I did some research here and come up with this:

• Check and declare each variable as null (if is the case) before start to use (as recommended):

!isset($_GET['myvar']) ? $_GET['myvar'] = 0:0;

*ok this one is simple but works fine, you can start to use the variable everywhere after this line

• Using array to cover all cases:

$myvars = array( 'var1', 'var2', 'var3');
foreach($myvars as $key)
    !isset($_GET[$key]) ? $_GET[$key] =0:0;

*after that you are free to use your variables (var1, var2, var3 ... etc),

PS.: function receiving a JSON object should be better (or a simple string with separator for explode/implode);

... Better approaches are welcome :)

---

UPDATE:

Use $_REQUEST instead of $_GET, this way you cover both $_GET and $_POST variables.

!isset($_REQUEST[$key]) ? $_REQUEST[$key] =0:0;

Answer 12

Well, you could get by with just if($_GET['myvar'] == 'something') since that condition presumes that the variable also exists. If it doesn't, the expression will also result in false.

I think it's ok to do this inside conditional statements like above. No harm done really.

Answer 13

Sadly that's the only way to do it. But there are approaches for dealing with larger arrays. For instance something like this:

$required = array('myvar', 'foo', 'bar', 'baz');
$missing = array_diff($required, array_keys($_GET));

The variable $missing now contains a list of values that are required, but missing from the $_GET array. You can use the $missing array to display a message to the visitor.

Or you can use something like that:

$required = array('myvar', 'foo', 'bar', 'baz');
$missing = array_diff($required, array_keys($_GET));
foreach($missing as $m ) {
    $_GET[$m] = null;
}

Now each required element at least has a default value. You can now use if($_GET['myvar'] == 'something') without worrying that the key isn't set.

Update

One other way to clean up the code would be using a function that checks if the value is set.

function getValue($key) {
    if (!isset($_GET[$key])) {
        return false;
    }
    return $_GET[$key];
}

if (getValue('myvar') == 'something') {
    // Do something
}

Answer 14

My question is, exist any way to do this without declare the variable twice?

No, there is no way to do this correctly without doing two checks. I hate it, too.

One way to work around it would be to import all relevant GET variables at one central point into an array or object of some sort (Most MVC frameworks do this automatically) and setting all properties that are needed later. (Instead of accessing request variables across the code.)