CODEWITHSUNDEEP
javascriptecmascript-6
MortenMoulder
MortenMoulder

Reputation: 6656

Remove object from array if it is contained in another array

I am trying to remove an object from an array, if that object's property (unique) is included in the other array. I know I can do a nested for-loop like this:

for(i = 0; i < array.length; i++) {
    for(j = 0; j < array2.length; j++) {
        if(array[i].Email === array2[j].Email) {
            //remove array[i] object from the array
        }
    }
}

Or whatever. Something like that. Is there an ES6 filter for that? I can easily do a filter up against a regular array with strings, but doing it with an array of objects is a bit more tricky.

Upvotes: 5

Views: 9914

Answers (6)

Rajesh
Rajesh

Reputation: 24955

If you are fine using ES6, you can even look into array.find, array.filter or array.some.

Array.findIndex

const result = array.filter(x => {
    return array2.findIndex(t => t.Email === x.Email) === -1;
});

Array.some

const result = array.filter(x => {
    return !array2.some(t => t.Email === x.Email);
});

Upvotes: 11

gurvinder372
gurvinder372

Reputation: 68443

Not very optimal, but try this

array = array.filter( function( item ){
  return array2.filter( function( item2 ){
    return item.Email == item2.Email;
  }).length == 0;
});

Try with find as well, it won't iterate all the elements and will break after first match itself

array = array.filter( function( item ){
  return array2.find( function( item2 ){
    return item.Email == item2.Email;
  }) == undefined;
});

Upvotes: 3

Harun KARATAŞ
Harun KARATAŞ

Reputation: 116

You can use shift function. here it's example.

http://www.w3schools.com/js/tryit.asp?filename=tryjs_array_shift
for(i = 0; i < array.length; i++) {
    for(j = 0; j < array2.length; j++) {
        if(array[i].Email === array2[j].Email) {
            array.shift(array[i].Email);
        }
    }
}

Upvotes: -2

Emil S. J&#248;rgensen
Emil S. J&#248;rgensen

Reputation: 6366

How about writing a function, passing the parameters and simply collecting the output?

function arrNotInArrKey(arr1, arr2, key) {
  for (var i = 0; i < arr1.length; i++) {
    for (var j = 0; j < arr2.length; j++) {
      if (arr1[i][key] === arr2[j][key]) {
        arr1.splice(i, 1);
        i--;
      }
    }
  }
  return arr1;
}
console.log(
  arrNotInArrKey([{
    name: 1
  }, {
    name: 3
  }, {
    name: 2
  }], [{
    name: 2
  }], "name")
);

Upvotes: -1

Nina Scholz
Nina Scholz

Reputation: 386883

You could use a Set with ES6

var array = [/* your data */],
    array2 = [/* your data */],
    set = new Set(...array2.map(a => a.Email));

array = array.filter(a => !set.has(a.Email));

Upvotes: 3

Pumayk26
Pumayk26

Reputation: 565

Try this one.... :) 

if(array[i].Email === array2[j].Email){
   // splice(Index you want to remove,to witch element)
   array1.splice(i,1);
}

splice() can remove element of your array. You need to pass witch element. witch element is the start of delete. How many elements should delete. That's 1.. :)

Upvotes: -1

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