Reputation: 1003
i have new problem with JPA in EJB3 my stacktrace are:
Caused by: javax.persistence.NonUniqueResultException: More than one result was returned from Query.getSingleResult()
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.throwNonUniqueResultException(EJBQueryImpl.java:1207)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.getSingleResult(EJBQueryImpl.java:722)
at com.DAO.CartDAO.checkUserID(CartDAO.java:47)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at org.glassfish.ejb.security.application.EJBSecurityManager.runMethod(EJBSecurityManager.java:1056)
at org.glassfish.ejb.security.application.EJBSecurityManager.invoke(EJBSecurityManager.java:1128)
at com.sun.ejb.containers.BaseContainer.invokeBeanMethod(BaseContainer.java:5292)
at com.sun.ejb.EjbInvocation.invokeBeanMethod(EjbInvocation.java:615)
at com.sun.ejb.containers.interceptors.AroundInvokeChainImpl.invokeNext(InterceptorManager.java:797)
at com.sun.ejb.EjbInvocation.proceed(EjbInvocation.java:567)
at com.sun.ejb.containers.interceptors.SystemInterceptorProxy.doAround(SystemInterceptorProxy.java:157)
at com.sun.ejb.containers.interceptors.SystemInterceptorProxy.aroundInvoke(SystemInterceptorProxy.java:139)
at sun.reflect.GeneratedMethodAccessor206.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at com.sun.ejb.containers.interceptors.AroundInvokeInterceptor.intercept(InterceptorManager.java:858)
at com.sun.ejb.containers.interceptors.AroundInvokeChainImpl.invokeNext(InterceptorManager.java:797)
at com.sun.ejb.co
i create one commandbutton to use for add item to cart, and i write one method to add item to cart in DB, i was check if userid and itemid != null, item quantity will add to 1, it mean when i have userid 1 add itemid 1 into cart, my method will check if it existed, item quantity will add 1 to item quantity in cart table, i can do it with one item, but if i add more item two into cart, it mean i add itemid is 2 into cart table, next i add more quantity of itemid 1 into db it throw exception More than one result. . . i know it can't have two instance at the same time, but i don't know how to solve it? Please help me
my addTocart method
public void addtoCart(Items item){
this.items = item;
if(cartDAO.checkUserID(getMemberLoginController().getUser().getUserid()) != null &&
cartDAO.checkItemid(items.getItemid()) != null){
cart = cartDAO.checkUserID(getMemberLoginController().getUser().getUserid());
int updateQuantity = cart.getCartQuantity() + 1;
cart.setCartQuantity(updateQuantity);
// chuyen so luong sang kieu du lieu big decimal
java.math.BigDecimal bigQuantity = new java.math.BigDecimal(String.valueOf(updateQuantity));
// so tien cua san pham = so luong x don gia
BigDecimal updatePrice = items.getPrice().multiply(bigQuantity);
cart.setPrice(updatePrice);
cart = cartDAO.updateCart(cart);
}else if(cartDAO.checkUserID(getMemberLoginController().getUser().getUserid()) != null &&
cartDAO.checkItemid(items.getItemid()) == null){
cart = cartDAO.checkUserID(getMemberLoginController().getUser().getUserid());
cartPk.setUserid(getMemberLoginController().getUser().getUserid());
cartPk.setItemid(item.getItemid());
cart.setCartPK(cartPk);
cart.setCartQuantity(1);
cart.setPrice(item.getPrice());
cart = cartDAO.addCart(cart);
}else {
cartPk.setItemid(item.getItemid());
cartPk.setUserid(getMemberLoginController().getUser().getUserid());
cart.setCartPK(cartPk);
cart.setCartQuantity(1);
cart.setPrice(item.getPrice());
cart = cartDAO.addCart(cart);
}
}
my select statement
@NamedQuery(name = "Cart.findByUserid", query = "SELECT c FROM Cart c WHERE c.cartPK.userid = :userid")
my checkuseridMethod
public Cart checkUserID(int id){
Cart cart = null;
try {
Query query = em.createNamedQuery("Cart.findByUserid");
query.setParameter("userid", id);
return (Cart) query.getSingleResult();
} catch (NoResultException e) {
return null;
}
}
Upvotes: 0
Views: 14680
Reputation: 1
I was having the same issue and found yours.
Adding to what @Bozho said, you can also:
getFirstResult()
method, if you already know that your database have duplicated values, or...LIMIT
clause to your raw query.I found out the hard way that it is more secure to use one of those methods instead of calling getSingleResult()
.
Upvotes: 0
Reputation: 597342
Well, it seems like your database has more carts for this user (which is a plausible scenario if you store user history)
You can either make sure that there is no more than one record in the database (by deleting older carts when a new one is created, for example), or use Query.setMaxResults(1)
and something like ORDER BY dateCreated
in your query.
Upvotes: 8