CODEWITHSUNDEEP
rpython-2.7rpy2
Dieter
Dieter

Reputation: 2659

Load r-script or block of code from AWS and Python 2.7 into R, via rpy2

Best

I've a R-script, which is located on my amazon S3 Bucket. What I want to do is, I would like to create a python 2.7 programm which can run R-scripts, (which are located and streamed via a S3-bucket). To do this, i would like to use the rpy2 library (without downloading the script itself temp. (thus : s3.get_object() unstead of s3.download_file() )).

Main question:

how do I load, the R-script into R, without downloading it. because : 

def __init__(self, r_script):
    self._r = robjects.r
    self._r.source(r_script.read())

or

def __init__(self, r_script):
    self._r = robjects.r
    self._r.source(r_script)

Doesn't work ... because it is not a location-string but already the code itself

Here is the content of my test script : 

rm(list = ls())

test1<- function(){}

test2<- function(){}

test3<- function(){}

execute<- function(){

  a <- c(1,2,3)
  c <- c(1,2,3)
  b <- c(1,2,3)

  r <- data.frame(a,b,c)

  return(r)
}

Kind regards

Upvotes: 1

Views: 165

Answers (1)

lgautier
lgautier

Reputation: 11565

rpy2 can let you parse a string as R code before evaluating it, and this is used in an helper class making a Python namespace out of the string containing R code (See Calling Custom functions from Python using rpy2).

from rpy2.robjects.packages import STAP
mymodule = STAP(r_script, "mymodule")

# call a function
mymodule.execute()

Note: I am seeing rm(list=ls)() at the beginning of your R script. If your R script is meant to be a library it should not assume anything about the frame in which it is executed. To help with that, the class STAP above will execute the R code in a new enviroment (not R's GlobalEnv).

Upvotes: 2

Related Questions