Reputation: 420
I want template specilization with two parameters in one function. Here is a sample of code.
#include <iostream>
#include <string>
template <typename T>
class Printer
{
public:
T value;
Printer(T value)
{
this->value = value;
}
void print();
};
template <typename T> void Printer<T>::print()
{
std::cout << value << "\n";
}
template <> void Printer<std::string>::print()
{
std::cout << "\"" << value <<"\"\n";
}
template <> void Printer<const char *>::print()
{
std::cout << "\"" << value <<"\"\n";
}
int main()
{
Printer<int> print1(2);
Printer<std::string> print2("Printing string");
Printer<const char *> print3("Printing char*");
print1.print();
print2.print();
print3.print();
}
Is there a way I can make the template speciazation for std::string
and const char *
in one function. I want this because they are doing the same thing.
Upvotes: 2
Views: 52
Reputation: 170289
You can use traits to add indirection on the specific behavior, based on type.
#include <iostream>
#include <string>
template <typename T>
class Printer
{
public:
T value;
Printer(T value)
{
this->value = value;
}
void print();
};
template<typename T>
struct PrinterTypeTraits {
static constexpr char* prefix = "";
static constexpr char* postfix = "";
};
template<>
struct PrinterTypeTraits<std::string> {
static constexpr char prefix = '\"';
static constexpr char postfix = '\"';
};
template<>
struct PrinterTypeTraits<const char*> : PrinterTypeTraits<std::string> {};
template <typename T> void Printer<T>::print()
{
using Traits = PrinterTypeTraits<T>;
std::cout << Traits::prefix << value << Traits::postfix << '\n';
}
int main()
{
Printer<int> print1(2);
Printer<std::string> print2("Printing string");
Printer<const char *> print3("Printing char*");
print1.print();
print2.print();
print3.print();
return 0;
}
Upvotes: 3