CODEWITHSUNDEEP
php
NineCattoRules
NineCattoRules

Reputation: 2428

PHP deleting images editing location

I have this function:

function deleteImage($image){
    //$image is a varchar like 2016/10/example.jpg from MySQL
    $myArray = explode('/', $image);

    $result = $s3->deleteObject(array(
        'Bucket' => $bucket,
        'Key'    => 'uploads/avatars/'.$myArray[0].'/'.$myArray[1].'/xs-'.$myArray[2]
    ));
}

Basically for $image = 2016/10/example.jpg

I need to delete the image located in 

uploads/avatars/2016/10/xs-example.jpg

I tried to figure it out the problem for hours but it's not working and seems impossible to debug.

Upvotes: 1

Views: 36

Answers (2)

sadok-f
sadok-f

Reputation: 1447

You're calling your function with an Array as argument, instead of deleteImage(array($verify['image'])); you should call it deleteImage($verify['image']);

Upvotes: 1

Phil
Phil

Reputation: 164760

I'd go for something like this

$key = sprintf('uploads/avatars/%s/xs-%s',
        ltrim(dirname($image), '/'), basename($image));

The ltrim is probably overkill but it's just in case your $image variable starts with a /.

This should handle any path depth you throw at it.

See

Upvotes: 3

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