CODEWITHSUNDEEP
php
StubbornShowaGuy
StubbornShowaGuy

Reputation: 269

Get class name of executed static function without namespace

Calling get_called_class() in PHP from a static function gives you the class name of the function, including the namespace if called from outside that namespace, it seems.

Is there a way to acquire the class name without the namespace?

(Obviously I understand that it would be possible to examine the string returned by get_called_class() and do some hackish stuff, but I am hoping there is a less hackish way to do it)

Upvotes: 4

Views: 3378

Answers (2)

AlSan
AlSan

Reputation: 392

You can use:

 /**
 * Get the class "basename" of the given object / class.
 *
 * @param  string|object  $class
 * @return string
 */
function class_basename($class)
{
    $class = is_object($class) ? get_class($class) : $class;

    return basename(str_replace('\\', '/', $class));
}

Upvotes: 0

user1465368
user1465368

Reputation:

Acquiring the class name without a namespace

Yes, you can do it using the ReflectionClass. Since your question relates to doing this from within a static method, you can get the class name like so:

$reflect = new \ReflectionClass(get_called_class());
$reflect->getShortName();

This uses the ReflectionClass constructor by passing a string with the fully namespaced name of the class to be inspected.

There is a similar question at How do I get an object's unqualified (short) class name? however it does not refer to doing this within a static method and so the examples pass an instantiated object to the ReflectionClass constructor.

Upvotes: 8

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