CODEWITHSUNDEEP
grep
user762579
user762579

Reputation:

grep : how to output the results in a file without the numbered lines?

I am trying to extract a sub-string from each line in a file between 2 groups of characters :

each line in the input file is :

https://github.com/myname/repo1 | GitHub - repo description
https://github.com/myname/repo2 | GitHub - repo description
https://github.com/myname/repo3 | GitHub - repo description
....
https://github.com/myname/repoN | GitHub - repo description

I extract the sub-string between "https://github.com/" and " | GitHub" to get :

 myname/repo1
 myname/repo2
 myname/repo3
 ...
 myname/repoN

And I use GNU grep. :

 grep -nPo 'github.com\/\K.*?(?= \|)' ~/Desktop/forksonGithub.txt

This displays the correct list in the console with line number

 1:myname/repo1
 2:myname/repo2
 3:myname/repo3
 ...
 4:myname/repoN

how can I get this list in an output file without the lin numbers ? thanks for feedback

Upvotes: 1

Views: 47

Answers (1)

Tamas Rev
Tamas Rev

Reputation: 7164

The option -n is responsible for the line numbers. You just need to remove it:

grep -Po 'github.com\/\K.*?(?= \|)' ~/Desktop/forksonGithub.txt
myname/repo1
myname/repo2
myname/repo3
...
myname/repoN

Upvotes: 1

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