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pythonarraysdatetimenumpy
hm8
hm8

Reputation: 1523

Convert numpy array to list of datetimes

I have a 2D array of dates of the form:

[Y Y Y ... ]
[M M M ... ]
[D D D ... ]
[H H H ... ]
[M M M ... ]
[S S S ... ]

So it looks like

data = np.array([
    [2015, 2015, 2015, 2015, 2015, 2015], # ...
    [   1,    1,    1,    1,    1,    1],
    [   1,    1,    1,    2,    2,    2],
    [  23,   23,   23,    0,    0,    0],
    [   4,    5,    5,   37,   37,   37],
    [  59,    1,    2,   25,   27,   29]
])

What would be the best way to convert this into one list of datetime objects?

Upvotes: 7

Views: 25949

Answers (2)

Eric
Eric

Reputation: 97691

If you want np.datetime64 objects, then this works:

import functools

units = 'YMDhms'
first_vals = np.array([1970, 1, 1, 0, 0, 0])
epoch = np.datetime64('1970')

results = functools.reduce(
    np.add,
    [
        d.astype('timedelta64[{}]'.format(unit))
        for d, unit in zip(data - first_vals[:,np.newaxis], units)
    ],
    epoch
)

Which gives:

array(['2015-01-01T23:04:59',
       '2015-01-01T23:05:01',
       '2015-01-01T23:05:02',
       '2015-01-02T00:37:25',
       '2015-01-02T00:37:27',
       '2015-01-02T00:37:29'], dtype='datetime64[s]')

Upvotes: 0

Def_Os
Def_Os

Reputation: 5467

import datetime
import numpy as np

data = np.array(
    [[2015, 2015, 2015, 2015, 2015, 2015],
     [   1,    1,    1,    1,    1,    1],
     [   1,    1,    1,    2,    2,    2],
     [  23,   23,   23,    0,    0,    0],
     [   4,    5,    5,   37,   37,   37],
     [  59,    1,    2,   25,   27,   29]]
)

# Transpose the data so that columns become rows.
data = data.T

# A simple list comprehension does the trick, '*' making sure
# the values are unpacked for 'datetime.datetime'.
new_data = [datetime.datetime(*x) for x in data]

print(new_data)

[datetime.datetime(2015, 1, 1, 23, 4, 59), datetime.datetime(2015, 1, 1, 23, 5, 1), datetime.datetime(2015, 1, 1, 23, 5, 2), datetime.datetime(2015, 1, 2, 0, 37, 25), datetime.datetime(2015, 1, 2, 0, 37, 27), datetime.datetime(2015, 1, 2, 0, 37, 29)]

Upvotes: 7

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