c++: How to flip the binary values of each bit in int

Question

Suppose I have an integer int a

In c++, as this int uses 4 bytes(32 bits) of memory, all bits would be occupied by either 1's or 0's. So, I wish to flip the values of each bit. That is, wherever in each bit there is 1 convert it to 0 and 0 to 1.

Is there an easy way to go about this?

Edit: I also want to play with boolean algebra also. That is if I can execute basic boolean operations like addition, subtraction, etc.

Answer 1

Here is an example of bitwise NOT operator:

#include <iostream>

int main()
{
    int a = 0;
    int x = ~a;
    unsigned int y = ~a;
    std::cout << x << '\n';
    std::cout << y << '\n';
}

Output:

-1
4294967295

For more information about binary operators and more try here

Answer 2

You're looking for the binary not operator (~).

So

int a = 0x04;
int b = ~a;

the value of b is 1111 1111 1111 1011 while the value of a is 0000 0000 0000 0100.

The wikipedia and the GNU C have plenty of information of these binary operators.