CODEWITHSUNDEEP
javajsonscala
LearningSlowly
LearningSlowly

Reputation: 9451

Scala read and parse JSON

I am new to Scala. I have a JSON file, entitled scala_input.json containing two items:

{
 "edges_file": "/path/edges.json.gz", 
 "seed_file": "/path/seed.json.gz"
}

I wish to open the file, parse and attribute two val from this file. I have tried:

val input_file = "/path/scala_input.json"
val json_data = JSON.parseFull(input_file)
val edges_file = json_data.get.asInstanceOf[Map[String, Any]]("edges_file").asInstanceOf[String]
val seeds_file = json_data.get.asInstanceOf[Map[String, Any]]("seed_file").asInstanceOf[String]]

However, this returns java.util.NoSuchElementException: None.get. What is it I have not defined? json_data and input_file are correct and I am sure that edges_file and seed_file exist.

Upvotes: 4

Views: 20751

Answers (2)

Powers
Powers

Reputation: 19328

os-lib and upickle are better options for reading and parsing JSON data.

val jsonString = os.read(os.pwd/"src"/"test"/"resources"/"scala_input.json")
val data = ujson.read(jsonString)
data("edges_file").str // "/path/edges.json.gz"
data("seed_file").str // "/path/seed.json.gz"

This code is way cleaner than what JSON.parseFull allows for. See here for more details on how to use these libs.

Upvotes: 6

Tzach Zohar
Tzach Zohar

Reputation: 37852

JSON.parseFull expects a JSON String, not a path to a file containing such a String. So - you should first load the file and then parse it:

val input_file = "./scala_input.json"
val json_content = scala.io.Source.fromFile(input_file).mkString
val json_data = JSON.parseFull(json_content)
// go on from there...

Upvotes: 6

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