CODEWITHSUNDEEP
phparraysjsonpost
fazil tm
fazil tm

Reputation: 299

How to convert json to string in php

I want to convert json data to String in php. This is my json data

    {
        "": [{
            "description": "hello, this is description speaking"
        }, {
            "fieldName": "myfile",
            "originalFilename": "image.png",
            "path": "/var/folders/rq/q_m4_21j3lqf1lw48fqttx_80000gn/T/ttzVoNPfBxMMirec1tJsnrd2.png",
            "headers": "[Object]",
            "size": "82745"
        }]
    }

I want to print "hello, this is description speaking" in my php file and also i want to upload my file. My php code is given below please correct it.

if ($_SERVER['REQUEST_METHOD'] == 'POST'){
 $json = file_get_contents("php://input");
    $json_obj = json_decode($json);

    echo $json_obj;

    echo $_POST['description'];

    $name = $_FILES['myfile']['name'];
$tmp_name = $_FILES['myfile']['tmp_name'];
$error = $_FILES['myfile']['error'];

if (!empty($name)) {
    $location = 'uploads/';

    if  (move_uploaded_file($tmp_name, $location.$name)){
        echo 'Uploaded';
    }

} else {
    echo 'please choose a file';
}
}  else {
    echo "error 2";
}

In this code errors are Undefined index: file in D:\xampp\htdocs\work. And without the fileupload code it shows nothing.

Upvotes: 1

Views: 3214

Answers (1)

Vinicius Dias
Vinicius Dias

Reputation: 689

If you just want to access the description property of your json, you can do the following:

$json_obj = json_decode($json, true);
$description = $json_obj[''][0]['description'];

Upvotes: 3

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