CODEWITHSUNDEEP
pythonsubstitutionencryption-symmetric
eneski
eneski

Reputation: 1665

How to encode Permutation of Substitution

I want to substitute from cypher text to plain text. But there can be n! possibilities where n is the number of characters

for example

cypher: [ a, b, c, d ]

plain : [ x, y, z, m ]

Let's say that I am sure one of the combination is correct plain text. In the example I know that there are 4! possible plaintext but I have to calculate it in python, because in my real problem n is 10.

I am asking for a piece of code or algorithm

Upvotes: 0

Views: 249

Answers (1)

Joran Beasley
Joran Beasley

Reputation: 114038

you need to do letter frequency analysis. read this article about it https://inventwithpython.com/hacking/chapter20.html

there is source there for frequency analysis in python

once you implement the source code from that tutorial you can then write

def test_solution(cypher,plaintext,encrypted_text):
    tab = string.transtab(cypher,plaintext)
    decrypted = encrypted_text.translate(tab)
    return (englishFreqMatchScore(decrypted),plaintext, decrypted)

tests = [test_solution(cypher,k,enc_text) for k in itertools.permutations(plain)]
print "SOLUTION:",max(tests)

note that this assumes the plaintext will be English ... letter frequency will be different for different languages (I think at least)

unfortunately this problem is np hard i think ... in order to find the best solution you must explore the entire solution space (so as N increases length of plaintext alphabet it gets alot harder...)

Upvotes: 1

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