CODEWITHSUNDEEP
node.jsgulpdel
Manish Singh
Manish Singh

Reputation: 538

gulp clean is not working in correct manner

I have directory structure like this.

dist
|--client
   |--assets
      |--images
   |--bower_components
|--server
|--.bower.json

I am trying to clean dist folder, except assets/images folder.

But when i execute this command in dryRun mode, it doesn't remove assets/images file. But after disabling it, it remove all the files and folder.

gulp.task('clean:dist', () => {
   del.sync([
    `${paths.dist}/!(.git*|.openshift|Procfile)**`,
     `${paths.dist}/client/**`,
    `!${paths.dist}/client/assets`,
    `!${paths.dist}/client/assets/**`], {
    //dryRun: true
  });
  //console.log('dELETE FIELSE ARE: ' + JSON.stringify(value));
});

value of used constant is:

${paths.dist} ='dist';

Upvotes: 0

Views: 850

Answers (1)

Sven Schoenung
Sven Schoenung

Reputation: 30574

The offical del documentation states the following:

The glob pattern ** matches all children and the parent.

So this won't work:

del.sync(['public/assets/**', '!public/assets/goat.png']);

You have to explicitly ignore the parent directories too:

del.sync(['public/assets/**', '!public/assets', '!public/assets/goat.png']);

In your case you delete dist/client/**, which includes the dist/client directory itself. If you just ignore dist/client/assets/** the dist/client directory is still deleted.

You need to explicitly ignore the dist/client directory:

gulp.task('clean:dist', () => {
   del.sync([
    `${paths.dist}/!(.git*|.openshift|Procfile)**`,
    `${paths.dist}/client/**`,
    `!${paths.dist}/client`,
    `!${paths.dist}/client/assets/**`]);
});

Upvotes: 1

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