CODEWITHSUNDEEP
pythonregex
Evgeniy Michurin
Evgeniy Michurin

Reputation: 73

Regular expression extract specific part

I have a string '(test)skip(test774)2;3(xx2324)'. The presence of the word 'skip' is necessary.

re.search('skip[(].+[)]', args[0]).group(0)

gives me 'skip(test774)', but not 'test774'. I can could use slicing [5:-1] to get 'test774', but it's too clumsy

What the easiest way to get only the value in brackets ('test774') using regular expressions?

Upvotes: 0

Views: 49

Answers (1)

cco
cco

Reputation: 6281

To isolate the text you want, use a capturing group around the part of the regex that matches that text.

re.search('skip[(]([^)]+)[)]', args[0]).group(1)

The change I made is where you have .+ (any non-empty sequence of characters), I have ([^)]+) (a capturing group containing a non-empty sequence of characters other than ); this means this part of the match stops just before the first ), rather than just before the last ), as .+ would).

regex101.com demo and explanation

Upvotes: 2

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