Reputation: 1302
I used below HTML & JS script to get ID and value of each element inside the form.
But, i need to get all these value and like below and added to the URL on top when user submit the form to redirect booking engine.
Getting below output on console.log:
someaction?fromLocation=undefined&departureDate=undefined&tripType=undefined&returnDate=undefined
HTML:
<form method="POST" id="bookingForm" action="someaction">
<div class="col-lg-6">
<div class="form-group">
<label for="fromLocation">From:</label>
<select class="select form-control input-lg" id="fromLocation" form="fromLocation" name="fromLocation" required>
<option value="">From</option>
<option value="ADL">Adelaide</option>
<option value="DRW">Darwin</option>
<option value="MEL">Melbourne</option>
<option value="PER">Perth</option>
</select>
</div>
<div class="form-group">
<label for="departure">Departure Date:</label>
<input class="departureDate form-control" id="departureDate" type="text" placeholder="Departure Date" name="Departure Date" required>
</div>
<div class="form-group" id="tripType">
<label for="tripType">Trip Type:</label>
<div class="col-lg-12">
<div class="col-lg-2">
<input class="radio tripType" id="ReturnTrip" type="radio" name="tripType" value="Return" checked="">Return
</div>
<div class="col-lg-2">
<input class="radio tripType" id="SingleTrip" type="radio" name="tripType" value="One-way">One-way
</div>
<div class="col-lg-8"></div>
</div>
</div>
</div>
<div class="col-lg-6">
<div class="form-group">
<label for="return">Return Date:</label>
<input class="returnDate form-control" type="text" id="returnDate" placeholder="Return Date" name="Return Date" required>
</div>
<div class="form-group" id="booking-btn--container">
<button class="btn btn-primary" type="submit">Submit</button>
</div>
</div>
</form>
JS:
var url = $("#bookingForm").attr("action") + "?";
var urlElements = [];
$("#bookingForm").find('.form-group').each(function(){
urlElements.push($(this).find('.form-control').attr("id") + "=" + $(this).find('.form-control').attr("value") || $(this).find('.form-control').attr("id") + "=" + $(this).find('.form-control').attr("value"));
});
urlElements = urlElements.join("&");
url += urlElements;
console.log(url);
Upvotes: 0
Views: 2684
Reputation: 97152
Just fix your name attributes to match your IDs, and use .serialize()
:
$("form").on("submit", function(event) {
event.preventDefault();
var form = $(this);
var url = form.attr('action') + '?' + form.serialize();
console.log(url);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="POST" id="bookingForm" action="someaction">
<div class="col-lg-6">
<div class="form-group">
<label for="fromLocation">From:</label>
<select class="select form-control input-lg" id="fromLocation" name="fromLocation" required>
<option value="">From</option>
<option value="ADL">Adelaide</option>
<option value="DRW">Darwin</option>
<option value="MEL">Melbourne</option>
<option value="PER">Perth</option>
</select>
</div>
<div class="form-group">
<label for="departure">Departure Date:</label>
<input class="departureDate form-control" id="departureDate" type="text" placeholder="Departure Date" name="departureDate" required>
</div>
<div class="form-group" id="tripType">
<label for="tripType">Trip Type:</label>
<div class="col-lg-12">
<div class="col-lg-2">
<input class="radio tripType" id="ReturnTrip" type="radio" name="tripType" value="Return" checked="">Return
</div>
<div class="col-lg-2">
<input class="radio tripType" id="SingleTrip" type="radio" name="tripType" value="One-way">One-way
</div>
<div class="col-lg-8"></div>
</div>
</div>
</div>
<div class="col-lg-6">
<div class="form-group">
<label for="return">Return Date:</label>
<input class="returnDate form-control" type="text" id="returnDate" placeholder="Return Date" name="returnDate" required>
</div>
<div class="form-group" id="booking-btn--container">
<button class="btn btn-primary" type="submit">Submit</button>
</div>
</div>
</form>
As a bonus, it will properly URL-encode your values.
Upvotes: 3
Reputation: 177
Try like this
var $input = $(this).find('.form-control');
urlElements.push($input.attr("id") + "=" + $input.val());
Upvotes: 2