CODEWITHSUNDEEP
javascriptstoppropagation
Joanna
Joanna

Reputation: 289

How to use event.stopPropagation() JavaScript

I have three elements with events assigned to them. How should I use event.stopPropagation so only events for elements #1 and #2 are executed, but not for #3? I put event.stopPropagation in element #2 as it stops bubbling. In my understanding, it should stop the triggering of the event in #3 but it doesn't seem to be working, all events are still being executed. Here is JS code:

    document.addEventListener("DOMContentLoaded", function() {
      document.querySelector('#element1').addEventListener('click', function(e) {
        console.log('Event in #element1 fired!');
      });

      document.querySelector('#element2').addEventListener('click', function(e) {
        event.stopPropagation();
        console.log('Event in #element2 fired!');
      });

      document.querySelector('#element3').addEventListener('click', function(e) {
        console.log('Event in #element3 fired!');
      });
    });
<div id="element3" class="element">
  Element 3
  <div id="element2" class="element">
    Element 2
    <div id="element1" class="element">
      Element 1
    </div>
  </div>
</div>

Upvotes: 0

Views: 3690

Answers (1)

NineBerry
NineBerry

Reputation: 28549

This line is wrong:

event.stopPropagation();

because the parameter with the event object passed to the function is named e.

You need to write this as:

e.stopPropagation();

Upvotes: 1

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