CODEWITHSUNDEEP
pythonlinuxsubprocessrpyc
user3516540
user3516540

Reputation: 73

Error running shell command with subprocess.check_call()

# -*- coding: utf-8 -*-
import rpyc
conn = rpyc.classic.connect(r"xx.xx.xx.xx")
s = conn.modules.subprocess.check_output(['file',u'`which dd`'])
print s

Output is:

`which dd`: cannot open ``which dd`' (No such file or directory)  

Process finished with exit code 0

When I execute manually on the command prompt it gives me proper output :

/bin/dd: symbolic link to /bin/dd.coreutils

Is there any Unicode error in my code

Upvotes: 0

Views: 224

Answers (1)

Moinuddin Quadri
Moinuddin Quadri

Reputation: 48092

It runs on the command prompt. But if you will call it through the subprocess (so will be with conn.modules.subprocess), it will give you error as:

>>> subprocess.check_call(['file', '`which python`'])
`which python`: cannot open ``which python`' (No such file or directory)

Because in shell, this will be executed as:

 mquadri$ file '`which python`'
`which python`: cannot open ``which python`' (No such file or directory)

But you want to run it as:

mquadri$ file `which python`
/usr/bin/python: Mach-O universal binary with 2 architectures
/usr/bin/python (for architecture i386):    Mach-O executable i386
/usr/bin/python (for architecture x86_64):  Mach-O 64-bit executable x86_64

In order to make the above command run, pass it as string to check_call with shell=True as:

>>> subprocess.check_call('file `which python`', shell=True)
/usr/bin/python: Mach-O universal binary with 2 architectures
/usr/bin/python (for architecture i386):    Mach-O executable i386
/usr/bin/python (for architecture x86_64):  Mach-O 64-bit executable x86_64

Upvotes: 0

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