CODEWITHSUNDEEP
javascriptstringcomparecomparison
Neel Kadia
Neel Kadia

Reputation: 77

How to compare two binary values in javascript/node js?

I have two string

var a = "10001010";
var b = "10110010";

So What will be the function to find out Similarities in two string, in that case that function will return this value;

A and B have 5 Digits in common; which are as below;

var a = "10001010";

var b = "10110010";

How can I get this values?

I need similarities between this two strings.

Upvotes: 2

Views: 5168

Answers (3)

Nina Scholz
Nina Scholz

Reputation: 386766

You could use bitwise XOR ^ with the numerical values of the strings and value of 28 - 1.

In the binary result, a single 1 means same value of a and b and 0 means not.

   value    binary  dec  comment
--------  --------  ---  ---------------------------------------
       a  10001010  138
       b  10110010  178
--------  --------  ---
       ^  00111000   56  it shows only the changed values with 1
2^^8 - 1  11111111  255
--------  --------  ---
       ^  11000111  199  result with 1 for same value, 0 for not


var a = parseInt("10001010", 2),
    b = parseInt("10110010", 2),
    result = (a ^ b) ^ (1 << 8) - 1;

console.log(result);
console.log(result.toString(2));

Upvotes: 4

Arjun Verma
Arjun Verma

Reputation: 20

I have written a logic to do this enter link description here

var test = "10001010";
var test2  = "10110010";
var testArray = test.split('');
var testArray2 = test2.split('');
var resultArray = [];
for(index = 0; testArray.length > index;index++ ){
    if(testArray[index] === testArray2[index]){
     resultArray.push(testArray[index])
    }else{
      resultArray.push("*")
    }
}

console.log(resultArray.join(""));

Upvotes: 0

Device
Device

Reputation: 567

I think, you can just compare them like this

("10001010" > "10110010") --> false
("10001010" < "10110010") --> true
("10001010" < "00110010") --> false
("00110010" == "00110010") --> true

Upvotes: 0

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