CODEWITHSUNDEEP
c#asp.net-mvcasp.net-mvc-3razor
level_zebra
level_zebra

Reputation: 1533

Multiple view models in Razor view

What would be the best way to for a razor view to handle multiple models? for an MVC3 application.

I have two models, both similar, but the Postcode field is required for one model and not for another

public class IrelandPostcodeLookupViewModel , IWithProgress
{
    readonly Progress _Progress = new Progress(Step.Delivery);

    public Progress Progress
    {
        get { return _Progress; }
    }

    [Required(ErrorMessage = "Please enter your house number or name")]
    [DisplayName("House number or name")]
    public string HouseNumber { get; set; }

    [StringLengthWithGenericMessage(50)]
    [DisplayName("Eircode")]
    public string Postcode { get; set; }

}

public class PostcodeLookupViewModel , IWithProgress
{
    readonly Progress _Progress = new Progress(Step.Delivery);

    public Progress Progress
    {
        get { return _Progress; }
    }

    [Required(ErrorMessage = "Please enter your house number or name")]
    [DisplayName("House number or name")]
    public string HouseNumber { get; set; }

    [StringLengthWithGenericMessage(50)]
    [Required(ErrorMessage = "Please enter your postcode")]
    [DisplayName("PostCode")]
    public string Postcode { get; set; }

}

In the controller I want to use a particular view model depending on a country I am passed. Something like

public virtual ActionResult PostcodeLookup(string country)
{
    if (country == Country.UnitedKingdom)
         return View(new PostcodeLookupViewModel());
    else
         return View(new IrelandPostcodeLookupViewModel());
}

I was handling this in the view with

@model dynamic

The problem I have with this is my view contains partial views 

@Html.Partial("~/Views/Shared/_Progress.cshtml", Model.Progress)

and I run into the error 'HtmlHelper' has no applicable method named 'Partial' but appears to have an extension method by that name. Extension methods cannot be dynamically dispatched'

Can anyone advise how I can handle the Partial View?

Thanks

Upvotes: 1

Views: 300

Answers (1)

Peter B
Peter B

Reputation: 24280

Because Model is dynamic, also Model.Progress produces a dynamic.
This is true for all properties and function calls on a dynamic object, no matter how deep you'd go.

To solve this you can typecast the Model.Progress object:

@Html.Partial("~/Views/Shared/_Progress.cshtml", (Progress)Model.Progress)

Upvotes: 1

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