CODEWITHSUNDEEP
scalaapache-sparkrdd
user1384205
user1384205

Reputation: 1291

Remove first element in RDD without using filter function

I have built an RDD from a file where each element in the RDD is section from the file separated by a delimiter.

val inputRDD1:RDD[(String,Long)] = myUtilities.paragraphFile(spark,path1)
                                              .coalesce(100*spark.defaultParallelism) 
                                              .zipWithIndex() //RDD[String, Long]
                                              .filter(f => f._2!=0)

The reason I do the last operation above (filter) is to remove the first index 0.

Is there a better way to remove the first element rather than to check each element for the index value as done above?

Thanks!

Upvotes: 4

Views: 3699

Answers (1)

Yuval Itzchakov
Yuval Itzchakov

Reputation: 149598

One possibility is to use RDD.mapPartitionsWithIndex and to remove the first element from the iterator at index 0:

val inputRDD = myUtilities
                .paragraphFile(spark,path1)
                .coalesce(100*spark.defaultParallelism) 
                .mapPartitionsWithIndex(
                   (index, it) => if (index == 0) it.drop(1) else it,
                    preservesPartitioning = true
                 )

This way, you only ever advance a single item on the first iterator, where all others remain untouched. Is this be more efficient? Probably. Anyway, I'd test both versions to see which one performs better.

Upvotes: 5

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