CODEWITHSUNDEEP
pythonpython-3.xpandas
Yashvardhan Nanavati
Yashvardhan Nanavati

Reputation: 192

unhashable type 'list' error

I am using the following code to count the number of occurrences of a particular number in a numpy array, sort the dictionary in a descending order and then return it

km_0 = [indian,chinese,italian,mexican,indian,indian,chinese,italian] #numpy array
#The ord_dict should be like this {indian:3, chinese:2, italian:2, mexican:1} 

def labels(cluster):
    label_count ={}
    for i in cluster[0]:
        if i in label_count:
            label_count[i] += 1
        else:
            label_count[i] =1
    ord_dict = OrderedDict(sorted(label_count.items(), key=lambda kv:kv[1], reverse=True))

    return ord_dict

function call

lc = labels(km_0)

However, it throws up the following error

<ipython-input-8-72f0a128bdd4> in labels(cluster)
      9     label_count ={}
     10     for i in cluster[0]:
---> 11             if i in label_count:
     12                 label_count[i] += 1
     13             else:

TypeError: unhashable type: 'list'

Upvotes: 0

Views: 477

Answers (2)

Goodies
Goodies

Reputation: 4681

Since the typo has already been addressed, I'll go another route. If you're looking specifically for numpy.array, then you can use MooingRawr's solution using Counter. However, to add a bit more performance, you can use a native Numpy counter such as count_nonzero.

import numpy as np

def cnt(arr):
    counts = {i: np.count_nonzero(arr == i) for i in range(arr.min(), arr.max() + 1)}
    return OrderedDict(sorted(counts.items(), key=lambda x: x[1], reverse=True))

x = np.random.random_integers(50, size=100)
y = np.random.random_integers(50, size=(10, 10))

Upvotes: 0

MooingRawr
MooingRawr

Reputation: 4991

Maybe instead of building your own counter you could employ from collection Counter:

from collections import Counter, OrderedDict
x = "hello world"
print(OrderedDict(sorted(Counter(x).items(), key=lambda t: t[1], reverse=True))) 
#prints OrderedDict([('l', 3), ('o', 2), (' ', 1), ('e', 1), ('d', 1), ('h', 1), ('r', 1), ('w', 1)])

I still don't know what j is for yours I'm guessing it's a typo for i

Edited:

Above works for normal Arrays but for numpy use the follow using numpy's unique() function call :

#replace array_name with like your `i`
unique, counts = numpy.unique(array_name, return_counts=True)

#Then zip them together to make a dictionary

counted = dict(zip(unique, counts))

#then toss it into OrderedDict

print(OrderedDict(sorted(counted.items(), key=lambda t: t[1], reverse=True)))

For more information on numpy.unique see here.

Upvotes: 1

Related Questions