Reputation: 6544
I'm trying to re-assign a variable in a loop, but I keep running into cannot assign to `cur_node` because it is borrowed
. Below I commented out the loop for simplicity, and it's the same problem. How do I handle this?
fn naive_largest_path(root: Rc<RefCell<Node>>) {
let mut cur_node = root.clone();
let cur_node_borrowed = cur_node.borrow();
// while cur_node_borrowed.has_children() {
let lc = cur_node_borrowed.left_child.as_ref().unwrap();
let left_child = cur_node_borrowed.left_child.as_ref().unwrap();
let right_child = cur_node_borrowed.right_child.as_ref().unwrap();
let left_val = left_child.borrow().value;
let right_val = right_child.borrow().value;
if left_val > right_val {
cur_node = left_child.clone();
} else {
cur_node = right_child.clone();
}
// }
}
struct Node {
value: i32,
row_num: i32,
position_in_row: i32,
left_child: Option<Rc<RefCell<Node>>>,
right_child: Option<Rc<RefCell<Node>>>,
}
impl Node {
fn new(val: i32, row: i32, pos_in_row: i32) -> Rc<RefCell<Node>> {
Rc::new(RefCell::new(Node {
value: val,
row_num: row,
position_in_row: pos_in_row,
left_child: None,
right_child: None,
}))
}
fn has_children(&self) -> bool {
self.left_child.is_some() || self.right_child.is_some()
}
}
Upvotes: 14
Views: 8706
Reputation: 14021
As the comments have said, you will need to restructure the code to make sure there is no borrow at the point where you want to assign to cur_node
. When dealing with Rc
you can also often get away with a few extra .clone()
, but that's cheating (and a little less efficient) :-).
Here's one way that compiles, taking advantage of Rust's blocks-are-expressions feature:
fn naive_largest_path(root: Rc<RefCell<Node>>) {
let mut cur_node = root.clone();
while cur_node.borrow().has_children() {
cur_node = {
let cur_node_borrowed = cur_node.borrow();
let lc = cur_node_borrowed.left_child.as_ref().unwrap();
let left_child = cur_node_borrowed.left_child.as_ref().unwrap();
let right_child = cur_node_borrowed.right_child.as_ref().unwrap();
let left_val = left_child.borrow().value;
let right_val = right_child.borrow().value;
if left_val > right_val {
left_child.clone()
} else {
right_child.clone()
}
};
}
}
Upvotes: 11