CODEWITHSUNDEEP
groovy
Bob Smelton
Bob Smelton

Reputation: 11

Groovy int vs integer function resolving

I recently started to learn Groovy and found not a natural behavior. 

class BasicRouter {
    int method_(first){
        return 1;
    }
    int method_(int first){
        return 2;
    }
    int method_(short second){
        return 3;
    }
    int method_(Integer first){
        return 4;
    }
}
br = new BasicRouter()
int x = 1
assert br.method_(x) == 4
assert br.method_((int)29) == 2

Why in the first case we are passing a variable of type int, we get 4 and not 2? I expect that method int method_(int) will be called.

Thanks.

Upvotes: 1

Views: 429

Answers (1)

Jim Speakman
Jim Speakman

Reputation: 76

The answer is here - http://docs.groovy-lang.org/latest/html/documentation/core-differences-java.html#_primitives_and_wrappers

Groovy uses objects for everything

This changes if you use CompileStatic

@groovy.transform.CompileStatic 
def fInt(int x) {new BasicRouter().method_(x)}
assert fInt(1) == 2

Upvotes: 4

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