CODEWITHSUNDEEP
c#
parsh
parsh

Reputation: 756

Initialize a List<List<T>> with default values

One of the ways of initializing List<T> with default values (of that type T) is

List<int> foo = new List<int>(new int[5]);

This would create a List with 5 zeroes. How would you do it for List<List<T>>?

I know we can do it using for loops or using Enumerate.Repeat (but that creates a deep copy) but would like to know if it can be done like above?

Upvotes: 1

Views: 7152

Answers (2)

apk
apk

Reputation: 1681

You can use a collection initializer to initialize a list with pre-determined values inline.

    object a, b, c, d, e;
    var foo = new List<object>()
    {
        a, b, c, d, e
    };

If you want to initialize a list with multiple instances of the same object, the List class doesn't give any solutions. You should probably stick to using a loop.

If you're looking for clever hacks, you can try:

var foo = new List<int>(Enumerable.Range(1, 5).Select(x => 42));
var bar = new List<string>(Enumerable.Range(1, 5).Select(x => "default"));
var far = new List<object>(Enumerable.Range(1, 5).Select(x => new object()));

But don't tell anyone I said that.

Upvotes: 2

Jonathan Allen
Jonathan Allen

Reputation: 70307

Short of creating your own subclass, there is no way to do it.

Upvotes: 0

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