CODEWITHSUNDEEP
javajson
Arraying
Arraying

Reputation: 179

JSON Object Returns Null

I have a very strange error when trying to get a number from a JSON API; the object seems to be null, although the URL (and code) should be correct.

org.json.JSONException: JSONObject["success"] not found.

I have tried printing out the JSONObject, and it gives me this:

{}

Here is my code:

    try{
        String url = "https://qrng.anu.edu.au/API/jsonI.php?length=1&type=uint16";
        JSONObject jsonObject = new JSONObject(new URL(url).openStream());
        String resultType = jsonObject.getString("success");
        if(resultType.equalsIgnoreCase("true")){
            JSONArray jsonArray = jsonObject.getJSONArray("data");
            int number = jsonArray.getInt(0);
           //do stuff with number
        }
        else{
            //unsuccessful
        }
    }
    catch(Exception e){
       //handle catch
    }

Upvotes: 1

Views: 2031

Answers (1)

Derrick
Derrick

Reputation: 4427

@Andreas is right, add this piece of code in your try block to convert input stream into a json string - 

InputStream is = new URL(url).openStream();
int ch;
StringBuilder sb = new StringBuilder();
while((ch = is.read()) != -1)
sb.append((char)ch);            
JSONObject jsonObject = new JSONObject(sb.toString());

Upvotes: 1

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