Reputation: 3926
I'm new to python and trying to plot a gaussian distribution having the function defined as
I plotted normal distribution P(x,y) and it's giving correct output. code and output are below.
Now I need to plot a conditional distribution and the output should like
. to do this I need to define a boundary condition for the equation. I tried to define a boundary condition but it's not working. the code which I tried is
but it's giving wrong output
please help me how to plot the same.
Thanks,
Upvotes: 1
Views: 6128
Reputation: 3325
You used the boundary condition on the wrong parameter, try to do it after creating the grid points.
R = np.arange(-4, 4, 0.1)
X, Y = np.meshgrid(R, R)
then validate X and Y based on the condition
valid_xy = np.sqrt(X**2+Y**2) >= 1
X = X[valid_xy]
Y = Y[valid_xy]
Then continue with the rest of the code.
Update
If you want just to reset values around the peak to zero, you can use the following code:
import numpy as np
import matplotlib.pyplot as plt
R = np.arange(-4, 4, 0.1)
X, Y = np.meshgrid(R, R)
Z = np.sum(np.exp(-0.5*(X**2+Y**2)))
P = (1/Z)*np.exp(-0.5*(X**2+Y**2))
# reset the peak
invalid_xy = (X**2+Y**2)<1
P[invalid_xy] = 0
# plot the result
fig = plt.figure(figsize=(10, 6))
ax = fig.add_subplot(111, projection='3d')
ax.scatter(X, Y, P, s=0.5, alpha=0.5)
plt.show()
Upvotes: 2
Reputation: 737
You can't use np.meshgrid
anymore because it will output a matrix where the coordinates of X and Y form a grid (hence its name) and not a custom shape (a grid minus a disc like you want):
However you can create your custom grid the following way:
R = np.arange(-,4,0.1)
xy_coord = np.array(((x,y) for x in R for y in R if (x*x + y*y) > 1))
X,Y = xy_coord.transpose()
X
# array([ 0. , 0. , 0. , ..., 3.9, 3.9, 3.9])
Y
# array([ 1.1, 1.2, 1.3, ..., 3.7, 3.8, 3.9])
Upvotes: 0