Reputation: 147
I try to get data from ajax pass from front page to my controller but i got only string to my controller so how can i separate it one by one.
this is form:
<form class="form-horizontal form" action="<?php print base_url() ?>insertCategory" method="post" enctype='multipart/form-data'>
<div class="box-body">
<div class="form-group">
<label for="inputEmail3" class="col-sm-2 control-label">name</label>
<div class="col-sm-10">
<input type="text" name='name' required class="form-control" id="inputEmail3" placeholder="Name">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-2 control-label">name</label>
<div class="col-sm-10">
<input type="text" name='test' required class="form-control" id="inputEmail3" placeholder="Name">
</div>
</div>
<div class="form-group">
<label for="inputPassword3" class="col-sm-2 control-label">Category Detail</label>
<div class="col-sm-10">
<textarea id="txtEditor" ></textarea>
</div>
</div>
<div class="form-group">
<label for="inputPassword3" class="col-sm-2 control-label">Image</label>
<div class="col-sm-10">
<input type="file" name="img" required class="form-control" >
</div>
</div>
</div>
<!-- /.box-body -->
<div class="box-footer">
<button type="submit" class="btn btn-info pull-right submit">Submit</button>
</div>
<!-- /.box-footer -->
</form>
this my code ajax:
$(".submit").click(function (e) {
e.preventDefault();
var data = $('.form').serialize();
var val = $("#txtEditor").Editor("getText");
var page = "<?php echo $page ?>";
var url = "<?php echo base_url(); ?>insertCategory"
$.ajax({
type: "POST",
url: url,
data:{
"data" : data
},
success: function (data) {
console.log(data);
}
});
return false;
});
and this is my controller:
public function insertCategory()
{
if($this->session->userdata('logged_in')==1){
$data = $this->input->post('data');
var_dump($data);
and this my data respond by ajax:
C:\....\AdminController.php:308:string 'name=dsfdsfs&test=dfsdf' (length=23)
Upvotes: 1
Views: 9281
Reputation: 1
use parse_str(); that can return array after parse string
public function insertCategory()
{
if($this->session->userdata('logged_in')==1){
$data = $this->input->post('data');
parse_str($data, $parseData);
var_dump($parseData);
Upvotes: 0
Reputation: 34
For reference, use this code below.
type: "POST",
url: url,
data: $('.form').serialize(),
success: function (data) {
console.log(data);
}
Use
data: $('.form').serialize()
instead of
var data = $('.form').serialize();
data:{
"data" : data
},
Upvotes: 1
Reputation: 8964
At the controller the contents of your form will be available in the $_POST
array. So the "name" field on your form can be accessed with $_POST['name']
.
That said, you will be better off using CodeIgniter's methods to retrieve this data.
For example:
$name = $this->input->post('name');
If, for learning purposes, you wanted to see everything "posted" to the controller this will do the trick.
public function insertCategory()
{
if($this->session->userdata('logged_in')==1)
{
$posted = $this->input->post(); //get all $_POST items
var_dump($posted);
}
}
Upvotes: 0
Reputation: 1244
Use this instead,
var_dump($_POST);
it is posted as same as post work
Upvotes: 1